Integrand size = 18, antiderivative size = 96 \[ \int x \left (c+a^2 c x^2\right ) \arctan (a x)^2 \, dx=\frac {c \left (1+a^2 x^2\right )}{12 a^2}-\frac {c x \arctan (a x)}{3 a}-\frac {c x \left (1+a^2 x^2\right ) \arctan (a x)}{6 a}+\frac {c \left (1+a^2 x^2\right )^2 \arctan (a x)^2}{4 a^2}+\frac {c \log \left (1+a^2 x^2\right )}{6 a^2} \]
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Time = 0.04 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {5050, 4998, 4930, 266} \[ \int x \left (c+a^2 c x^2\right ) \arctan (a x)^2 \, dx=\frac {c \left (a^2 x^2+1\right )^2 \arctan (a x)^2}{4 a^2}-\frac {c x \left (a^2 x^2+1\right ) \arctan (a x)}{6 a}+\frac {c \left (a^2 x^2+1\right )}{12 a^2}+\frac {c \log \left (a^2 x^2+1\right )}{6 a^2}-\frac {c x \arctan (a x)}{3 a} \]
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Rule 266
Rule 4930
Rule 4998
Rule 5050
Rubi steps \begin{align*} \text {integral}& = \frac {c \left (1+a^2 x^2\right )^2 \arctan (a x)^2}{4 a^2}-\frac {\int \left (c+a^2 c x^2\right ) \arctan (a x) \, dx}{2 a} \\ & = \frac {c \left (1+a^2 x^2\right )}{12 a^2}-\frac {c x \left (1+a^2 x^2\right ) \arctan (a x)}{6 a}+\frac {c \left (1+a^2 x^2\right )^2 \arctan (a x)^2}{4 a^2}-\frac {c \int \arctan (a x) \, dx}{3 a} \\ & = \frac {c \left (1+a^2 x^2\right )}{12 a^2}-\frac {c x \arctan (a x)}{3 a}-\frac {c x \left (1+a^2 x^2\right ) \arctan (a x)}{6 a}+\frac {c \left (1+a^2 x^2\right )^2 \arctan (a x)^2}{4 a^2}+\frac {1}{3} c \int \frac {x}{1+a^2 x^2} \, dx \\ & = \frac {c \left (1+a^2 x^2\right )}{12 a^2}-\frac {c x \arctan (a x)}{3 a}-\frac {c x \left (1+a^2 x^2\right ) \arctan (a x)}{6 a}+\frac {c \left (1+a^2 x^2\right )^2 \arctan (a x)^2}{4 a^2}+\frac {c \log \left (1+a^2 x^2\right )}{6 a^2} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.67 \[ \int x \left (c+a^2 c x^2\right ) \arctan (a x)^2 \, dx=\frac {c \left (a^2 x^2-2 a x \left (3+a^2 x^2\right ) \arctan (a x)+3 \left (1+a^2 x^2\right )^2 \arctan (a x)^2+2 \log \left (1+a^2 x^2\right )\right )}{12 a^2} \]
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Time = 0.25 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.91
method | result | size |
parts | \(\frac {a^{2} c \,x^{4} \arctan \left (a x \right )^{2}}{4}+\frac {c \,x^{2} \arctan \left (a x \right )^{2}}{2}+\frac {c \arctan \left (a x \right )^{2}}{4 a^{2}}-\frac {c \left (\frac {\arctan \left (a x \right ) x^{3} a^{3}}{3}+x \arctan \left (a x \right ) a -\frac {a^{2} x^{2}}{6}-\frac {\ln \left (a^{2} x^{2}+1\right )}{3}\right )}{2 a^{2}}\) | \(87\) |
derivativedivides | \(\frac {\frac {c \arctan \left (a x \right )^{2} a^{4} x^{4}}{4}+\frac {a^{2} c \,x^{2} \arctan \left (a x \right )^{2}}{2}+\frac {c \arctan \left (a x \right )^{2}}{4}-\frac {c \left (\frac {\arctan \left (a x \right ) x^{3} a^{3}}{3}+x \arctan \left (a x \right ) a -\frac {a^{2} x^{2}}{6}-\frac {\ln \left (a^{2} x^{2}+1\right )}{3}\right )}{2}}{a^{2}}\) | \(88\) |
default | \(\frac {\frac {c \arctan \left (a x \right )^{2} a^{4} x^{4}}{4}+\frac {a^{2} c \,x^{2} \arctan \left (a x \right )^{2}}{2}+\frac {c \arctan \left (a x \right )^{2}}{4}-\frac {c \left (\frac {\arctan \left (a x \right ) x^{3} a^{3}}{3}+x \arctan \left (a x \right ) a -\frac {a^{2} x^{2}}{6}-\frac {\ln \left (a^{2} x^{2}+1\right )}{3}\right )}{2}}{a^{2}}\) | \(88\) |
parallelrisch | \(\frac {3 c \arctan \left (a x \right )^{2} a^{4} x^{4}-2 c \arctan \left (a x \right ) a^{3} x^{3}+6 a^{2} c \,x^{2} \arctan \left (a x \right )^{2}+a^{2} c \,x^{2}-6 a c x \arctan \left (a x \right )+3 c \arctan \left (a x \right )^{2}+2 c \ln \left (a^{2} x^{2}+1\right )}{12 a^{2}}\) | \(89\) |
risch | \(-\frac {c \left (a^{2} x^{2}+1\right )^{2} \ln \left (i a x +1\right )^{2}}{16 a^{2}}+\frac {c \left (3 x^{4} \ln \left (-i a x +1\right ) a^{4}+2 i a^{3} x^{3}+6 a^{2} x^{2} \ln \left (-i a x +1\right )+6 i a x +3 \ln \left (-i a x +1\right )\right ) \ln \left (i a x +1\right )}{24 a^{2}}-\frac {a^{2} c \,x^{4} \ln \left (-i a x +1\right )^{2}}{16}-\frac {i a c \,x^{3} \ln \left (-i a x +1\right )}{12}-\frac {c \,x^{2} \ln \left (-i a x +1\right )^{2}}{8}-\frac {i c x \ln \left (-i a x +1\right )}{4 a}+\frac {c \,x^{2}}{12}-\frac {c \ln \left (-i a x +1\right )^{2}}{16 a^{2}}+\frac {c \ln \left (-a^{2} x^{2}-1\right )}{6 a^{2}}\) | \(206\) |
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Time = 0.25 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.77 \[ \int x \left (c+a^2 c x^2\right ) \arctan (a x)^2 \, dx=\frac {a^{2} c x^{2} + 3 \, {\left (a^{4} c x^{4} + 2 \, a^{2} c x^{2} + c\right )} \arctan \left (a x\right )^{2} - 2 \, {\left (a^{3} c x^{3} + 3 \, a c x\right )} \arctan \left (a x\right ) + 2 \, c \log \left (a^{2} x^{2} + 1\right )}{12 \, a^{2}} \]
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Time = 0.36 (sec) , antiderivative size = 94, normalized size of antiderivative = 0.98 \[ \int x \left (c+a^2 c x^2\right ) \arctan (a x)^2 \, dx=\begin {cases} \frac {a^{2} c x^{4} \operatorname {atan}^{2}{\left (a x \right )}}{4} - \frac {a c x^{3} \operatorname {atan}{\left (a x \right )}}{6} + \frac {c x^{2} \operatorname {atan}^{2}{\left (a x \right )}}{2} + \frac {c x^{2}}{12} - \frac {c x \operatorname {atan}{\left (a x \right )}}{2 a} + \frac {c \log {\left (x^{2} + \frac {1}{a^{2}} \right )}}{6 a^{2}} + \frac {c \operatorname {atan}^{2}{\left (a x \right )}}{4 a^{2}} & \text {for}\: a \neq 0 \\0 & \text {otherwise} \end {cases} \]
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Time = 0.19 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.91 \[ \int x \left (c+a^2 c x^2\right ) \arctan (a x)^2 \, dx=\frac {{\left (a^{2} c x^{2} + c\right )}^{2} \arctan \left (a x\right )^{2}}{4 \, a^{2} c} + \frac {{\left (c^{2} x^{2} + \frac {2 \, c^{2} \log \left (a^{2} x^{2} + 1\right )}{a^{2}}\right )} a - 2 \, {\left (a^{2} c^{2} x^{3} + 3 \, c^{2} x\right )} \arctan \left (a x\right )}{12 \, a c} \]
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\[ \int x \left (c+a^2 c x^2\right ) \arctan (a x)^2 \, dx=\int { {\left (a^{2} c x^{2} + c\right )} x \arctan \left (a x\right )^{2} \,d x } \]
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Time = 0.58 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.86 \[ \int x \left (c+a^2 c x^2\right ) \arctan (a x)^2 \, dx=\frac {c\,\left (6\,x^2\,{\mathrm {atan}\left (a\,x\right )}^2+x^2\right )}{12}+\frac {\frac {c\,\left (3\,{\mathrm {atan}\left (a\,x\right )}^2+2\,\ln \left (a^2\,x^2+1\right )\right )}{12}-\frac {a\,c\,x\,\mathrm {atan}\left (a\,x\right )}{2}}{a^2}+\frac {a^2\,c\,x^4\,{\mathrm {atan}\left (a\,x\right )}^2}{4}-\frac {a\,c\,x^3\,\mathrm {atan}\left (a\,x\right )}{6} \]
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